SOLUTION: Sue travels 5mph less than twice as fast as June. Starting at the same point and traveling in the same direction, they are 80 miles apart after 4 hours. Find their speeds.

Question 114219This question is from textbook
: Sue travels 5mph less than twice as fast as June. Starting at the same point and traveling in the same direction, they are 80 miles apart after 4 hours. Find their speeds. This question is from textbook

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Sue travels 5 mph less than twice as fast as June. Starting at the same point and traveling in the same direction, they are 80 miles apart after 4 hours. Find their speeds.
:
Let x = J's speed
:
It says, "Sue travels 5 mph less than twice as fast as June." So we can say:
(2x - 5) = S's speed
:
Using the statement: "Starting at the same point and traveling in the same
direction, they are 80 miles apart after 4 hours." we can say:
:
S's dist traveled - J's distance traveled = 80
:
Dist = Time * speed
:
4(2x-5) - 4x = 80
:
8x - 20 - 4x = 80
:
8x - 4x = 80 + 20; added 20 to both sides:
:
4x = 100
:
x = 100/4
:
x = 25mph is J's speed
:
Using (2x - 5)
2(25) - 5 =
50 - 5 = 45 mph is S's speed
:
:
Check our solution by finding the distance that each has traveled:
S: 4(45) = 180 mi
J: 4(25) = 100 mi
-----------------
Difference: 80 mi
:
How about this? Did this method seem understandable to you? Any questions
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