SOLUTION: A salesman drives from Ajax to Barrington, a distance of 130 mi, at a steady speed. He then increases his speed by 10 mi/h to drive the 158 mi from Barrington to Collins. If the se

Question 1137814: A salesman drives from Ajax to Barrington, a distance of 130 mi, at a steady speed. He then increases his speed by 10 mi/h to drive the 158 mi from Barrington to Collins. If the second leg of his trip took 2 min more time than the first leg, how fast was he driving between Ajax and Barrington?
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!

                          SPEED      TIME(hours)      DISTANCE

Ajax to Barrington          r         130/r              130

Barrington to Collins      r+10       158/(r+10)         158


Difference                           1/30

Second part, B to C, took 2 minutes MORE than first part.

Solve...
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