SOLUTION: At 8:00 a.m the Smith's left a campground,driving at 48mi/h. At 8:20 a.m the Garcia's left the same campground and followed the same route, driving at 60 mi/h. At what time did the

Question 113764This question is from textbook Algebra Structure and method
: At 8:00 a.m the Smith's left a campground,driving at 48mi/h. At 8:20 a.m the Garcia's left the same campground and followed the same route, driving at 60 mi/h. At what time did they overtake the Smith's?
Here is what I have but I don't know if it is right
60t=48(t+1/3)
60t=48t+16
60t-48t=48t-48t+16
12t=16
12t/12=16/12
t=14/12or 11/3
They overtook the Smiths at 1:20
Is this right? This question is from textbook Algebra Structure and method

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The Smiths and Garcias both travel the same distance
I'll just call the distance
To find their elapsed time, start a stopwatch when the
Garcias leave at 8:20. Stop the stopwatch when they meet.
Call that elapsed time hrs. But the Smiths have already been
driving for 20 min., so their time is hrs

hrs or,

This is the Garcias elapsed time
8:20 + 1 hr 20 min = 9:40 answer

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