SOLUTION: Emma launches her boat from point A on a bank of a straight river, 3km wide, and wants to reach Point B (8km downstream on the opposite bank) as quickly as possible. She could

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Question 1137355: Emma launches her boat from point A on a bank of a straight river, 3km wide, and wants to reach Point B (8km downstream on the opposite bank) as quickly as possible.
She could proceed in any of three ways:
- (a) Row her boat directly across the river to Point C and then run to B
- (b) Row directly to B
- (c) Row to some point D between C and B, and then run to B
If she can row 6km/h and run 8km/h, where should she land to reach B as soon as possible?
Note: We assume that the speed of the water is negligible compared with the speed at which she rows.

Found 2 solutions by mananth, ikleyn:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
Emma launches her boat from point A on a bank of a straight river, 3km wide, and wants to reach Point B (8km downstream on the opposite bank) as quickly as possible.

- Row her boat directly across the river to Point C and then run to B Time = distance / speed. Time AC + time CB = total time
Time taken will be 3/6 + 8/8 = 1.5 hours

- Row directly to B
The hypotenuse distance will be
time taken for this distance will be = 1.42 hours

- Row to some point D between C and B, and then run to B
Obviously this will take more time since rowing distance is greater than running distance.

Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
.

            While I agree with the  @mananth's  answers to  (a)  and  (b),  I totally disagree with his answer to  (c),  which is incorrect.


Let x be the "x-coordinate" of the intermediate "target" point D between points C and B on the opposite bank of the river.


Then the total time t(x) to get from  A to B  is


    t(x) =  +   hours.     (1)


The plot of this function is shown in the figure below, and it clearly shows that the function t(x) has a minimum between 0 and 8.




Plot y =  + 


To find the value of x which provides the minimum to t(x), take the derivative of t(x)


    t'(x) =  - ,


equate it to zero and solve the obtained equation for x


     -  = 0,

    8x = 

    64x^2 = 36(9+x^2)

    64x^2 = 36*9 + 36x^2

    64x^2 - 36x^2 = 324

    x^2 =  = 11.571

    x =  = 3.4 (approximately).



Answer.  The target point to minimize time is 3.4 kilometers from C to B,


         giving time  t(3.4) =  +  = 1.331 hours.

Solved.



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