SOLUTION: Suppose 579 spectators were present at a tennis match. Of the spectators, 123 were kids, and there were
twice as many men as women. How many men attended the match?
Algebra.Com
Question 1136825: Suppose 579 spectators were present at a tennis match. Of the spectators, 123 were kids, and there were
twice as many men as women. How many men attended the match?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
total spectators were 579.
123 were kids.
there were twice many men as women.
let m equal the number of men and w equal the number of women.
123 + m + w = 579.
subtract 123 from both sides of this equation to get m + w = 579 - 123.
simplify to get m + w = 456.
you are given that there were twice as meny men as women.
that makes m = 2w
replace m with 2w in the equation of m + w = 456 to get 2w + w = 456.
combine like terms to get 3w = 456.
solve for w to get w = 456 / 3 = 152.
since there were twice as many men as women, then m = 2 * 152 = 304.
total was 123 kids plus 304 men plus 152 women = 579.
304 = 2 * 152.
solution is confirmed to be good.
solution is that 304 men attended the match.
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