SOLUTION: A salesman drives from Ajax to Barrington, a distance of 147 mi, at a steady speed. He then increases his speed by 15 mi/h to drive the 190 mi from Barrington to Collins. If the se

Question 1132807: A salesman drives from Ajax to Barrington, a distance of 147 mi, at a steady speed. He then increases his speed by 15 mi/h to drive the 190 mi from Barrington to Collins. If the second leg of his trip took 5 min more time than the first leg, how fast was he driving between Ajax and Barrington?
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
r, speed of first leg of trip

                          SPEED       TIME        DISTANCE
Ajax to Barrington        r           147/r        147
Barrington to Collins    r+15         190/(r+15)   190

Difference                          5/60=1/12

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