SPEED        TIME       DISTANCE

TO SHOP         10           d/10         d

RETURN          12           d/12         d

Total                        11

With the time spent on the outbound leg/slower speed being T, the equation you need is one of DISTANCE, and is: 10T = 12(11 - T)

Correct answers:  

RELATED QUESTIONS

Leah went to the internet cafe traveling 20 mph and returned home traveling 10 mph. If... (answered by josmiceli)

Matt went to the park traveling 10 mph and returned home traveling 20 mph. If the total... (answered by ikleyn)

Practice Age word  Problem

Alfonso went to the internet cafe traveling 6 mph and... (answered by ewatrrr,josgarithmetic,ikleyn,greenestamps)

Kathryn went to the study group traveling 25 mph and returned home traveling 20 mph. If... (answered by Boreal)

Devin went to the park traveling 8 mph and returned home traveling 16 mph. If the total... (answered by josgarithmetic,ikleyn)

Zheng went to the park traveling 6 mph and returned home traveling 4 mph. If the total... (answered by josgarithmetic,ikleyn,greenestamps)

Nina went to the mall traveling 6mph and returned home traveling 15mph. If the total trip  (answered by josgarithmetic)

Nina went to the mall traveling 6mph and returned home traveling 15mph. If the total trip  (answered by Alan3354)

I have absolutely no idea how to solve this problem. I have a few other distance problems  (answered by josgarithmetic,Alan3354)