SOLUTION: An executive would arrive 10.0 min early for an appointment if traveling at 60.0 mi/h, or 5.0 min early if traveling at 45.0 mi/h. How much time is there until the appointment? I

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Question 1128025: An executive would arrive 10.0 min early for an appointment if traveling at 60.0 mi/h, or 5.0 min early if traveling at 45.0 mi/h. How much time is there until the appointment?
I am having trouble setting up an equation for this problem.
Found 2 solutions by ikleyn, Boreal:
Answer by ikleyn(52812)   (Show Source): You can put this solution on YOUR website!
.
Let D be the distance to travel, in miles.


Then the time traveling at the speed of 60 mph is   hours,

while the time traveling at the speed of 45 mph is   hours. 


We are given that the difference    -    is 10 minutes - 5 minutes = 5 minutes =  of an hour:


      -   = .


It is your basic equation, and the setup is just DONE.


To solve the equation, multiply its both sides by  180.  You will get


    4D - 3D = 15,

    D = 15    miles.


The appointment is scheduled at   hours + 10 minutes = 15 minutes + 10  minutes = 25 minutes counting from the time

the executive starts his journey.

Solved.

---------------

To see other similar solved problems,  look into the lesson
    - How far do you live from school?
in this site.

Your problem is non-standard and is different from that usually are offered in typical Math classes.

Since you are interested in such kind of problems,  I recommend you to look into my other lessons on Travel & Distance
that you will find in accompanied references to that lesson.

You will find there  A  LOT  of  unique  and  interesting   non-standard  Travel & Distance problems.


Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
time to appointment is x
x-10 minutes is 10 minutes early, x-5 is 5 minutes early
at 60 mph, he travels 1 mile a minute, and in x-10 minutes will travel x-10 miles
at 45 mph, he travels 3/4 a mile a minute, and in x-5 minutes will travel (3/4)(x-5) or (3/4)x-3.75
those two are equal since the starting and ending points are the same.
x-10=(3/4)x-3.75
(1/4)x=6.25
x=25 minutes ANSWER
10 minutes early means he travels 15 min at 60 mph and that is 15 miles
5 minutes early means he travels 20 min at 45 mph and that is 15 miles
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