SOLUTION: Hello! Please help me answer this problem. I've gotten the answer but unsure if it's correct or not: A cyclist and a jogger set out at 6:00AM from the same point, headed in the

Question 1125417: Hello! Please help me answer this problem. I've gotten the answer but unsure if it's correct or not:
A cyclist and a jogger set out at 6:00AM from the same point, headed in the same direction. The average speed of the cyclist is twice the average speed of the jogger. In one hour, the cyclist is 7 km ahead of the jogger. What is the rate of the cyclist?
The answer I've gotten so far is 2.3333...
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
jogger, r
cyclist, 2r
their speed of separation, r.

ONE hour, distance difference 7 km.

, rate multiplied by time is distance.

--------speed of jogger

-----------speed of cyclist
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