SOLUTION: Mang Gustin can climb a coconut tree at the rate of 10 ft. per minute and return at 20 ft.per minute. If it took him 3 minutes to climb and return, what is the height of the coconu

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Question 1123958: Mang Gustin can climb a coconut tree at the rate of 10 ft. per minute and return at 20 ft.per minute. If it took him 3 minutes to climb and return, what is the height of the coconut tree?
Found 2 solutions by ikleyn, josmiceli:
Answer by ikleyn(52787)   (Show Source): You can put this solution on YOUR website!
.
Let H be the height of the tree, in feet.


Then    is the time to climb the tree, while    is the time to return.


The total time is the sum   + ,  and your equation is


     +  = 3  minutes.


To solve it, multiply both sides of the equation by 20. You will get


2H + H = 60,

3H = 60  ====>  H = 60/3 = 20.


Answer.  The height of the tree is 20 ft.


Check.  The time to climb is  20/10 = 2 minutes.

        The time to return is  20/20 = 1 minute.

        2 + 1 = 3 minutes.   ! Correct !

--------------------

See the lesson
    - Climbing a coconut tree up and down
in this site - it contains practically the same problem !


Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Let = time in minutes to go up the tree
= time in minutes to go down the tree
Let = the height of the tree in feet
——————————-
Equation for going up:
(1)
Equation for going down:
(2)
—————————————
By substitution:
(2)
(2)
(2)
(2)
And
(1)
(1)
The tree is 20 ft high
——————————-
Check:
(2)
(2)
OK


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