SOLUTION: Carla and patrick rode stationary bikes for the same smoking of time. Carla rode at 8 miles per hour, and patrick rode at 4.5 miles per hour. If carla rode 2.63 miles farther than

Question 1123610: Carla and patrick rode stationary bikes for the same smoking of time. Carla rode at 8 miles per hour, and patrick rode at 4.5 miles per hour. If carla rode 2.63 miles farther than patrick. How Long did they use the bikes?

i cant solve it trying to figure out what order should i put it
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39630) (Show Source): You can put this solution on YOUR website!
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Carla rode at 8 miles per hour, and patrick rode at 4.5 miles per hour. If carla rode 2.63 miles farther than patrick. How Long did they use the bikes?
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Each rode for the same time? DURING the same time?

SPEED TIME DISTANCE CARLA 8 x d+2.63 PATRRICK 4.5 x d

Solve this for d.

Use value found for d to find x.

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(not the only way)
Answer by ikleyn(52878) (Show Source): You can put this solution on YOUR website!
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Carla and Patrick rode their bikes for the same amount of time.
Carla rode at 8 miles per hour, and Patrick rode at 4.5 miles per hour.
If Carla rode 2.63 miles farther than Patrick, how Long did they use the bikes?
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Pay attention on how I edited your post in order for it makes sense.

Your equation is THIS : Distance Carla rode - distance Patrick rode = 2.63 mile, or 8*t - 4.5t = 2.63 where t = "How Long did they use the bikes" is the unknown amount of time under the question. 8t -4.5t = 2.63 3.5t = 2.63 t = = 0.751429 hours.

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