SOLUTION: Cody left the park traveling 12 mph. Then, 2 hours later, Jeff left traveling the same direction at 18 mph. How long until Jeff catches up with Cody?

Question 1123150: Cody left the park traveling 12 mph. Then, 2 hours later, Jeff left traveling the same direction at 18 mph. How long until Jeff catches up with Cody?
Answer by ikleyn(52794) (Show Source): You can put this solution on YOUR website!
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Let "t" be the time after Jeff left the park.


The the time after Cody left the park is (t+2) hours.


Jeff traveled the distance of 18*t miles.

Cody traveled 12*(t+2) miles.


At the moment Jeff catches up with Cody, they cover the same distance.

It gives you an equation


    18t = 12(t+2).


    18t = 12t + 24,

    18t - 12t = 24

     6t = 24

      t = 24/6 = 4 hours.


Answer.  4 hours.

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