SOLUTION: Cody and Jeff both leave the park at the same time, but in opposite directions. If Jeff travels 7 mph faster than Cody and after 5 hours they are 105 miles apart, how fast is each
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Question 1123148: Cody and Jeff both leave the park at the same time, but in opposite directions. If Jeff travels 7 mph faster than Cody and after 5 hours they are 105 miles apart, how fast is each traveling?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
C=x mph
J=x+7 mph
in 5 hours, they go 5(x)+5(x+7)=105 miles apart
5x+5x+35=105
10x=70
x=7 mph for Cody
x+7=14 mph for Jeff
That is 21 mph apart and 5 hours is 105 miles
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