SOLUTION: a cart is moving at a initial velocity of 2.0 m/s and accelerates at 3.3 m/s^2 for 33 m . how fast is it going at the end of the motion

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Question 1123033: a cart is moving at a initial velocity of 2.0 m/s and accelerates at 3.3 m/s^2 for 33 m . how fast is it going at the end of the motion
Found 3 solutions by ikleyn, josmiceli, Alan3354:
Answer by ikleyn(52787)   (Show Source): You can put this solution on YOUR website!
.
Let me apply the Energy conservation law.


The change of kinetic energy is   - .


The work of the force which provided the given acceleration "a", is  (ma)*d,

where d is the distance (of 33 m in your case).


So, the conservation of energy gives an equation


     -  = ma*d.


Cancel the mass "m" in both sides.  You will get


     -  = a*d.


Hence,   = ad + , 

and finally


    V = .


Now substitute the given values into the formula and calculate the answer.


It is, probably, the shortest way to solve the problem and to explain the solution.


Did I pass your exam ?

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What is your textbook in Physics ?



Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!

m/sec
m/sec2
m




Solve for using quadratic formula
Let = final velocity
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
a cart is moving at a initial velocity of 2.0 m/s and accelerates at 3.3 m/s^2 for 33 m . how fast is it going at the end of the motion
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Is it 33 meters, or 33 minutes?
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