Let M be the mass of the coal before drying. Since it contains 2.4% of water, after drying the mass will be M - 0.024*M. Let C be the mass of carbon in this coal. Then the condition says= 0.71. Therefore, C = 0.71*(M-0.024*M) = 0.71*M*(1-0.024), or = 0.71*(1-0.024) = 0.693 (approximately), or 69.3%. Answer. Before drying, the percentage of carbon in the coal is 69.3%, approximately (rounded to one decimal place).