SOLUTION: Town X and Town Y are 560 KM apart. At 11 A.M., a van leaves Town X for Town Y, Travelling at a constant rate of speed. At the same time, a bus leaves for Town Y from Town X, also

Question 1118790: Town X and Town Y are 560 KM apart. At 11 A.M., a van leaves Town X for Town Y, Travelling at a constant rate of speed. At the same time, a bus leaves for Town Y from Town X, also travelling at a constant rate of speed. The 2 vehicle pass each other at 1.20 P.M. The average speed of the van is 60 km per hr faster than the bus.
a) Find the van's average rate of speed?
b) How far is the bus from Town X when it passes the van?
Found 3 solutions by josgarithmetic, MathTherapy, Alan3354:
Answer by josgarithmetic(39623)   (Show Source): You can put this solution on YOUR website!
11AM to 1:20PM is 2 hours 20 minutes.

r, bus speed
r+60, van speed

Distance used between the two was 560 kilometers.

Solve.

-

------bus's average speed
-
-----van's average speed
-
--------how far the bus traveled from town Y.
---------how far was bus from town X after 2 hour 20 minutes
Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!
Town X and Town Y are 560 KM apart. At 11 A.M., a van leaves Town X for Town Y, Travelling at a constant rate of speed. At the same time, a bus leaves for Town Y from Town X, also travelling at a constant rate of speed. The 2 vehicle pass each other at 1.20 P.M. The average speed of the van is 60 km per hr faster than the bus.
a) Find the van's average rate of speed?
b) How far is the bus from Town X when it passes the van?

The van leaves Town X for Town Y, and the bus leaves for Town Y from Town X?
From what I've read, both left from TOWN X and headed to TOWN Y. Is that what you meant? I don't think so!!
From what you're saying, both left TOWN X, and if so, that's the only time they'd be "together." You need to change this!!
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Travelling at a constant rate of speed.
==================
There is no "rate of speed"
---
There's rate, and there's speed.
--- Confirmed by the Dept. of Redundancy Dept.

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