.
Let r be the speed of the slower-moving car, in miles per hour.
Then the speed of the faster car is (r+10) mph.
The distance equation is
4r + 4*(r+10) = 456.
4r + 4r + 40 = 456
8r = 456-40 = 416 ====> r = = 52.
Answer. The speed of the slower-moving car is 52 mph.
Solved.
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