SOLUTION: find csc 0 if 0 is an angle in standard position whose terminal side passes through (-12, 5)

Question 1112428: find csc 0 if 0 is an angle in standard position whose terminal side passes through (-12, 5)
Found 2 solutions by stanbon, ikleyn:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find csc 0 if 0 is an angle in standard position whose terminal side passes through (-12, 5)
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csc = 1/sin = r/y
r = sqrt[12^2+5^2] = sqrt[144+25] = sqrt(169) = 13
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csc(t) = 13/5
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Ans: Theta = arcsin(5/13) = 22.62 degrees
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Cheers,
Stan H.
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Answer by ikleyn(53765) (Show Source): You can put this solution on YOUR website!
.
The correct answer is

= = .

The problem does not ask about the value of , but the other tutor for some (unknown to me) reason gives the value of as the answer, and makes it I N C O R R E C T L Y. The correct value of (although, again, the problem does not ask about it !) is = = 180 - 22.62 = 157.38 degrees.

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