SOLUTION: At 09 00 car A starts its journey and traveling at 70 km/h at 10 30 car B started from the same place and traveled steadily on the same road. Car B took 3 1/2 h to catch up with ca

Question 1110001: At 09 00 car A starts its journey and traveling at 70 km/h at 10 30 car B started from the same place and traveled steadily on the same road. Car B took 3 1/2 h to catch up with car A. Find the speed of Car B.

Found 2 solutions by ankor@dixie-net.com, greenestamps:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
At 09 00 car A starts its journey and traveling at 70 km/h
at 10 30 car B started from the same place and traveled steadily on the same road.
Car B took 3 1/2 h to catch up with car A.
Find the speed of Car B.
let b = speed of car b
:
When car B catches up with A, the will have traveled the same distance
Write a distance equation: dist = speed * time
Car A traveled 1.5 hrs longer than car B. Car A traveled: 3.5 + 1.5 = 5 hrs
:
B's dist = A's dist
3.5b = 70(5)
3.5b = 350
b = 350/3.5
b = 100 km/hr
Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!

The second car started 1.5 hours after the first; and it caught up to the first car after traveling 3.5 hours.

So the first car traveled the same distance in 5 hours that the second car traveled in 3.5 hours.

The ratio of travel times is 5:3.5, or 10:7; since the distances are the same when the second car catches up to the first, that means the ratio of speeds is 7:10.

If the ratio of speeds is 7:10 and the first car traveled at 70 km/h, the second car traveled at 100 km/hr.
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