SOLUTION: an aircraft carrier made a trip to dry dock and back. it took 11 hours to get there and 8 hours to get back. the aircraft averaged 22 mph on the return trip. what was it’s speed g
Question 1109328: an aircraft carrier made a trip to dry dock and back. it took 11 hours to get there and 8 hours to get back. the aircraft averaged 22 mph on the return trip. what was it’s speed going to dry dock? Answer by ikleyn(52925) (Show Source): You can put this solution on YOUR website! .
the distance in each way is the same:
11*v = 22*8 (each way distance),
where v is the unknown rate. From the equation,
v = = 16 miles per hour was the average rate on the way to the dock.