SOLUTION: Trains on the Glasgow Subway depart every 4 minutes, and a complete circuit takes 24 minutes. Ewan sets off at 8.30 am on a train round in one direction at the same time as another

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Question 1108544: Trains on the Glasgow Subway depart every 4 minutes, and a complete circuit takes 24 minutes. Ewan sets off at 8.30 am on a train round in one direction at the same time as another train leaves in the opposite direction. How many trains will he pass on a complete circuit back to his starting station? (Do not count trains at the start or end station.)
Answer by ikleyn(52772)   (Show Source): You can put this solution on YOUR website!
.
First, you should count those trains that started at or after 8:30 am in the opposite direction.

There are 6 of them that started at 8:30 am, 8:34 am, 8:38 am, 8:42 am, 8:46 am and 8:50 am.


In addition to it, you should count those trains that started before 8:30 in the opposite direction and arrived 
to the starting/ending station after 8:30 am.


Ewan will meet those trains too.    (Accounting for these trains and not missing them is the major point of the solution to this problem !)


These are the trains that 

started at 8:06 am     arrived at 8:30 am     (should not be counted)

           8:10 am                8:34 am     (counts)

           8:14 am                8:38 am     (counts)

           8:18 am                8:42 am     (counts)

           8:22 am                8:46 am     (counts)

           8:24 am                8:50 am     (counts)


The number of such trains is  5.


So, the total is  6 + 5 = 11, and I do not count the trains at the start or end station, as the condition requires.

This problem was just solved once at the link
https://www.algebra.com/algebra/homework/word/travel/Travel_Word_Problems.faq.question.1108213.html

https://www.algebra.com/algebra/homework/word/travel/Travel_Word_Problems.faq.question.1108213.html


See also the lesson
    - More complicated but still elementary logic problems, Problem 2
in this site.


I reproduced this solution here AGAIN for your convenience.



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