For the general case, if D is the distance, then Jake spends hours. (1)
Mike spends + = = = = hours. (2)
In (2), the denominator is LESS THAN 5, so the fraction (2) is GREATER than fraction (1),
which means, again, that Mike is slower.
firstpart 6 d/12 d/2 secondpart 4 d/8 d/2 total d(1/12+1/8) d