SOLUTION: I am needing some help figuring this one out: a plane makes a 1125km trip in 4 1/4 hrs and makes the return trip in 3 hours. if the pane travels at a constant speed and the win

Question 1106905: I am needing some help figuring this one out:
a plane makes a 1125km trip in 4 1/4 hrs and makes the return trip in 3 hours.
if the pane travels at a constant speed and the wind blows at a constant rate, find the plane's airspeed and the speed of the wind
I honestly dont even know where to start. thank you!

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39630)   (Show Source): You can put this solution on YOUR website!
for distance D, time T, and constant rate of travel R.

r, travel speed if no wind present
w, speed of wind

The speed going WITH the wind is larger than the speed going AGAINST wind.

SPEED TIME DISTANCE GOING, AGAINST WIND r-w 4&1/4 1125 RETURN, WiTH WIND r+w 3 1125

Basic System from the problem description:

-

Using Elimination Method,

ANSWER:

Answer by ikleyn(52897)   (Show Source): You can put this solution on YOUR website!
.
It is a typical "tailwind and headwind" word problem.

See the lessons
    - Wind and Current problems
    - Selected problems from the archive on a plane flying with and against the wind
in this site.

In these lessons you will find the detailed solutions of many similar problems.
Consider them as samples. Read them attentively.
Then solve your problem by substituting your data.
In this way you will learn how to solve similar problems once and for all.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the section "Word problems", the topic "Travel and Distance problems".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

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