SOLUTION: The intensity of a radio signal from the radio station varies inversely as the square of the distance from the station. Suppose intensity is 8000 units at a distance of 2 miles. W

Question 1105192: The intensity of a radio signal from the radio station varies inversely as the square of the distance from the station. Suppose intensity is 8000 units at a distance of 2 miles. What will the intensity be at a distance of 12 miles? Round your answer to the nearest unit.
a.
205 units
b.
222 units
c.
248 units
d.
186 units

Found 2 solutions by Boreal, Alan3354:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
I=k/d^2
8000=k/2^2
k=32000.
Use k in second part.
I=32000/12^2=32000/144=222.2 units or 222
B.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The intensity of a radio signal from the radio station varies inversely as the square of the distance from the station. Suppose intensity is 8000 units at a distance of 2 miles. What will the intensity be at a distance of 12 miles? Round your answer to the nearest unit.
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6 times the distance --> (1/6)^2 times the intensity.
8000/36 = 222 units
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