1.  I am glad that after my notice at

        https://www.algebra.com/algebra/homework/word/travel/Travel_Word_Problems.faq.question.1099270.html

    you changed the problem formulation.

    Now the problem is correctly posed and is solvable.



2.  Let x be the distance from the apartment building to the parking lot, and 
    let y the distance from the parking lot to the office.


    Then you have these two equations

    x + y = 42,            (1)     (total distance)

     +  =  +      (2)    ("time" equation")


    Multiply eq(2) by 120 (both sides). You will get

    2x + 30y = 3x + 10y,   or

    x = 20y.              (3)


    Now express y = 42-x from eq(1)  and substitute it into eq(3). You will get

    x = 20*(42-x),

    x = 20*42 - 20x  ====>  21x = 20*42  ====>  x =  = 20*2 = 40.


    Thus, the distance x is 40 kilometers.  Then the distance  y is 42-40 = 2 km.

    And the total time of the Carl's travel is   = 1 hour and 10 minutes.


    So, they both arrive to the office at  7:10 am.