.
The problem says that Ryan, who is now 60 feet behind Nelson, should catch him up in 30 seconds.
So, Ryan should running in ft/s = 2 ft/s faster than Nelson, who runs at 6 ft/s.
Hence, Ryan' speed must be 6 + 2 = 8 ft/s.
Solved.
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Nice problem. Thanks for posting it.
If it is interesting to you, there is a bunch (a huge collection) of Travel and Distance problems/lessons in this site.
They are listed in the lesson
- OVERVIEW of lessons on Travel and Distance
from which you can easily observe them.
Actually, all these lessons are the part of the online textbook in Algebra-I, which I created for many years
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The textbook is free of charge (as everything else in this site).
The explicit link to the textbook is
https://www.algebra.com/algebra/homework/word/travel/OVERVIEW-of-lessons-on-Travel-and-Distance.lesson
You can save this link to your archive and use it when it is needed.