SOLUTION: Two cyclists leave towns
132mi
apart at the same time and travel toward each other. One cyclist travels
4
/mih
faster than the other. If they meet in
3
hours, what
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Question 1093430: Two cyclists leave towns
132mi
apart at the same time and travel toward each other. One cyclist travels
4
/mih
faster than the other. If they meet in
3
hours, what is the rate of each cyclist?
Found 2 solutions by rothauserc, Alan3354:
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
let x be the slower cyclist, then
:
3x + (x+4)3 = 132
:
3x +3x +12 = 132
:
6x = 120
:
x = 20
:
********************************
rate of slower cyclist is 20 mph
rate of faster cyclist is 24 mph
********************************
:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Two cyclists leave towns 132mi apart at the same time and travel toward each other. One cyclist travels 4 /mih [sic] **** It's mi/hr *** faster than the other. If they meet in 3 hours, what is the rate of each cyclist?
--------------
Speeds in opposite directions are added.
-------
Step 1, find the sum of the speeds.
--
The difference is given, = 4 mi/hr.
-----------
Call the speeds x & y
--
x + y = sum
x - y = 4
---------------------- Add
2x = sum + 4
etc.
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