SOLUTION: Two friends are 60 miles apart. They decide to ride their bikes to meet each other. Sally starts from the college and heads east, riding at a rate of 21 mph. At the same time, T
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Question 109324This question is from textbook ALGEBRA 1
: Two friends are 60 miles apart. They decide to ride their bikes to meet each other. Sally starts from the college and heads east, riding at a rate of 21 mph. At the same time, Teresa starts from the river and heads west, riding at a rate of 15 mph.
a. draw a diagram showing the college and the river 60 miles apart and the two cyclists riding toward each other (I can do that)!
b. How far does each cyclist ride in t hours? (i need help with this one)!
c. When the two cyclists meet, what must be true about the distances they have ridden? Write and solve an equation to find when they meet.(oh boy--i need help here too)!!!
I just am not sure what to do here..I am thinking d=r.t
rate distance time
sally 21 mph 60 miles t
teresa 15mps 60 miles t
60=21t for sally
60=15t for teresa
I am lost now.....I just don't know what to do, even if I was correct so far....
This question is from textbook ALGEBRA 1
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Sally starts from the college and heads east, riding at a rate of 21 mph.
At the same time, Teresa starts from the river and heads west, riding at a rate of 15 mph.
a. draw a diagram showing the college and the river 60 miles apart and the two cyclists riding toward each other (I can do that)!
b. How far does each cyclist ride in t hours? (i need help with this one)!
Sally DATA:
Rate = 21 mph; Time = t hours; Distance = rt = 21t miles
-----------
Theresa DATA;
Rate = 15 mph; time =- t hours; Distance = rt = 15t
-----------------------
c. When the two cyclists meet, what must be true about the distances they have ridden? Write and solve an equation to find when they meet.(oh boy--i need help here too)!!!
EQUATION:
Sally distance + Thresa distance = 60
21t + 15t = 60
36t = 60
6t = 10
t = (5/3) hour
t = 1 hour 40 minutes
==================
Cheers,
Stan H.
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