Question 1093131: A bullet is shot straight up into the air from ground level. It reaches a maximum height at h= 821m.
calculate the initial speed of the bullet, in m/s.
Using the previous results, calculate the total flight time, t, in seconds, until the bullet reaches the ground.
Answer by ikleyn(52747) (Show Source):
You can put this solution on YOUR website! .
Solution 1 (Physics)
Apply the energy conservation law:
= mgH,
where m is the mass of the body, v is its initial vertical speed (m/s),
g is the gravity acceleration (9.81 m/s^2), H is the maximal height.
Canceling m in both sides and simplifying, you get
= 2gH, or v = = 126.9 m/s.
By knowing the initial speed, the physicist momentarily will find the time to reach the maximum height
t = = = 12.9 seconds.
and the total time to get the ground is twice of this, i.e. 25.8 seconds.
Solution 2 (School math)
Your expression for the height above the ground as a function of time is this quadratic function
h(t) = .
The maximum is achieved at t = = = and is equal to
H = = = = .
So, you obtain practically the same equation
H = , or = 2*9.8*H, or = = = 126.9 m/s,
and the same answer for vertical speed.
Solved.
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To wider your horizon and to get a solid base regarding problems on projectile launched vertically up, see the lessons
- Problem on a projectile moving vertically up and down
- Problem on an arrow shot vertically upward
- Problem on a ball thrown vertically up from the top of a tower
- Problem on a toy rocket launched vertically up from a tall platform
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook under the topic "Projectiles launched/thrown and moving vertically up and dawn".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.
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