SOLUTION: Christopher ran m miles at r miles per hour and arrived on time. Then the distance was increased 7 miles. How fast did he have to run to travel the new distance in the same amount
Question 1091242: Christopher ran m miles at r miles per hour and arrived on time. Then the distance was increased 7 miles. How fast did he have to run to travel the new distance in the same amount of time? Found 2 solutions by ankor@dixie-net.com, MathTherapy:Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website! Christopher ran m miles at r miles per hour and arrived on time.
time =
Then the distance was increased 7 miles.
(m+7)
How fast did he have to run to travel the new distance in the same amount of time?
let s = the increase in speed required to do this =
cross multiply
m(r+s) = r(m+7)
distribute
mr + ms = mr + 7r
subtract mr from both sides
ms = 7r
s = mph the increase in speed
"How fast to run to travel the new distance in the same amount of time?
r + mph is the required speed Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
Christopher ran m miles at r miles per hour and arrived on time. Then the distance was increased 7 miles. How fast did he have to run to travel the new distance in the same amount of time?
Time =
New distance: m + 7
Speed at which to travel: