SOLUTION: Twelve hours after a convict escapes from prison, a guard begins to pursue him. If the convict travels at 10 mph on foot, and the guard travels at 70 mph by car, how far from the p

Question 1089679: Twelve hours after a convict escapes from prison, a guard begins to pursue him. If the convict travels at 10 mph on foot, and the guard travels at 70 mph by car, how far from the prison will the convict be caught by the guard?
Found 2 solutions by josmiceli, MathTherapy:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Find convict's headstart in miles

mi
----------------------
Let = distance the guard travels until
the guard catches convict
Let = time in hrs until the guard catches
up with the convict
-------------------------------------------
Equation for the convict:
(1)
Equation for the guard:
(2)
-----------------------
(1)
Plug (2) into (1)
(1)
(1)
(1)
and
(2)
(2)
The convict is caught 140 mi from the prison
----------------
check:
(1)
(1)
(1)
(1)
OK
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Twelve hours after a convict escapes from prison, a guard begins to pursue him. If the convict travels at 10 mph on foot, and the guard travels at 70 mph by car, how far from the prison will the convict be caught by the guard?

Let distance from the prison that the convict was caught, be D
Then we get the following TIME equation:
7D = D + 840 -------- Multiplying by LCD, 70
7D � D = 840
6D = 840
D, or distance from prison where convict was caught =
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