SOLUTION: A plane travels at a speed of 155⁢mph in still air. Flying with a tailwind, the plane is clocked over a distance of 950 miles. Flying against a headwind, it takes 3 hours lon

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Question 1080617: A plane travels at a speed of 155⁢mph in still air. Flying with a tailwind, the plane is clocked over a distance of 950 miles. Flying against a headwind, it takes 3 hours longer to complete the return trip. What was the wind velocity?
I think I should have (950/(155-w)) - (950/(155+w)) = 3
but I'm unsure of what to do.
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
Initial table of data before analyzing the time quantities; w is tailwind speed.
               SPEED        TIME         DISTANCE

WITHWIND       155+w                     950
AGAINSTWD      155-w                     950


               SPEED        TIME            DISTANCE

WITHWIND       155+w        950/(155+w)      950
AGAINSTWD      155-w        950/(155-w)      950

Concentrate on the part of the description, Flying against a headwind, it takes
3 hours longer to complete the return trip.
This means .

The rest is arithmetic to solve the equation for , the speed of the wind.













......using you will get:




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