SOLUTION: A model rocket is launched with an initial velocity of 250ft/s. The height,h,in feet, of the rocket t seconds after the launch is given be h=-16t^2+250t. How many seconds after the
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Question 1078537: A model rocket is launched with an initial velocity of 250ft/s. The height,h,in feet, of the rocket t seconds after the launch is given be h=-16t^2+250t. How many seconds after the launch will the rocket be 150ft above the ground? Round to the nearest hundredth of a second.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
h=-16t^2+250t. How many seconds after the launch will the rocket be 150ft above the ground?
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h=-16t^2+250t = 150
Solve for t
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