SOLUTION: Two cyclists leave a city at the same​ time, one going east and the other going west. The west bound cyclist bikes at 3 mph faster than the east bound cyclist. After 5 hours
Question 1074056: Two cyclists leave a city at the same time, one going east and the other going west. The west bound cyclist bikes at 3 mph faster than the east bound cyclist. After 5 hours they are 225 miles apart. How fast is each cyclist riding? Answer by ikleyn(52831) (Show Source): You can put this solution on YOUR website! .
Your equation is
5r + 5*(r+3) = 225.
5r + 5r + 15 = 225 ---> 10r = 210 ---> r = = 21.
Answer. The speed of the slower cyclist is 21 mph. The speed of the faster syclist is 21+3 = 24 mph.