# SOLUTION: luoise walked for 2 hours then ran for 1.5 hours if she ran twice as long as she walks and the total trip was 20 miles the how fast did she run? I am working on trying to set th

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 Question 107013: luoise walked for 2 hours then ran for 1.5 hours if she ran twice as long as she walks and the total trip was 20 miles the how fast did she run? I am working on trying to set this up i have x to equal walking spd and 2x for running speed I know the rate is 3.5 hours together woulit be 3.5 = (x + 2x) / 20 ??? Answer by ptaylor(2058)   (Show Source): You can put this solution on YOUR website!I am working on trying to set this up i have x to equal walking spd and 2x for running speed I know the rate is 3.5 hours together woulit be 3.5 = (x + 2x) / 20 ??? AT LEAST YOU ARE GIVING IT A SHOT BUT I THINK YOU ARE TRYING TO MAKE IT HARDER THAN IT REALLY IS. TRY TO FOLLOW MY APPROACH. distance(d) equals rate(r) times time(t) or d=rt; r=d/t and t=d/r I'm assuming you mean "-----twice as fast---not twice as long--" AS YOU HAVE DONE, WE'LL LET: Let x=walking speed Then 2x=running speed Distance she walks=x*2 or 2x (rate she walks times time) Distance she runs=2x*1.5 or 3x (rate she runs times time) Now we know (actually we are told) that the distance she walks plus the distance she runs equals 20 mi, so: 2x+3x=20 collect like terms 5x=20 divide both sides by 5 x=4 mi/hr-----------------------------walking speed 2x=2*4=8 mi/hr-----------------------------running speed CK 2*4+1.5*8=20 8+12=20 20=20 Hope this helps---ptaylor