SOLUTION: Two​ joggers, one averaging 5 mph and one averaging 4 ​mph, start from a designated initial point. The slower jogger arrives at the end of the run 35 minute

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Question 1068895: Two​ joggers, one averaging 5

mph and one averaging 4

​mph, start from a designated initial point. The slower jogger arrives at the end of the run 35

minutes after the other jogger. Find the distance of the run.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39625)   (Show Source): You can put this solution on YOUR website!
                speed        time          distance

Fast             5           t               d

Slow             4           t+35/60         d




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-
Answer by ikleyn(52855)   (Show Source): You can put this solution on YOUR website!
.
Two​ joggers, one averaging 5 mph and one averaging 4 ​mph, start from a designated initial point.
The slower jogger arrives at the end of the run 35 minutes after the other jogger. Find the distance of the run.
~~~~~~~~~~~~~~~~~~~~~~ 

 =     (the difference of jogging times is 35 minutes)

Multiply both sides by 60. You will get

15D - 12D = 35,

3D = 35  --->  D =  =  mile.

Answer. The distance is miles.


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