SOLUTION: Problem Page Keisha drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 6 hours. When Keisha drove home, there was no traffic and

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Question 1067866: Problem Page
Keisha drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took
6
hours. When Keisha drove home, there was no traffic and the trip only took
4
hours. If her average rate was
22
miles per hour faster on the trip home, how far away does Keisha live from the mountains?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39623)   (Show Source): You can put this solution on YOUR website!
Constant Travel Rates Rule, RT=D for RATE, TIME, DISTANCE
                    SPEED      TIME      DISTANCE
GOING                 r          6          d
RETURNING            r+22        4          d


System of Equations

Same d both directions;


Solve for r, the speed GOING TO the mountains.
Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!

Problem Page
Keisha drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took
6
hours. When Keisha drove home, there was no traffic and the trip only took
4
hours. If her average rate was
22
miles per hour faster on the trip home, how far away does Keisha live from the mountains?
Let the distance to the mountains be D

Then speed to the mountains = 

Speed on return trip = 

We then get the following SPEED equation: 

Solve this to get a distance of: 

That's all...nothing CONFUSING and/or COMPLEX! 

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