SOLUTION: supposs you have entered a 73-mile biathlon that consists of a tun and a bicycle race. during your run, your average velocity is 5 miles per hour, and during your bicycle race, you

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Question 1064448: supposs you have entered a 73-mile biathlon that consists of a tun and a bicycle race. during your run, your average velocity is 5 miles per hour, and during your bicycle race, your average velocity is 29 miles pet hour. you finish the race in 5 hours. what is the distance of the run? what is the distance of the bicycle race?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
                SPEED       TIME     DISTANCE
RUN              5           x        5x
BICYCLE         29           y        29y
TOTAL                        5        73










DISTANCE OF THE BICYCLE


---------the bicycle portion

DISTANCE OF THE RUN PORTION

--------running portion
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

supposs you have entered a 73-mile biathlon that consists of a tun and a bicycle race. during your run, your average velocity is 5 miles per hour, and during your bicycle race, your average velocity is 29 miles pet hour. you finish the race in 5 hours. what is the distance of the run? what is the distance of the bicycle race?
Let distance of the run be D

Then distance of the bicycle race = 73 - D

We then get the following TIME equation: 

Solve this equation for D, the distance of the run

Subtract value for D from 73 to get the distance of the bicycle race

That's it....nothing COMPLEX and/or CONFUSING! 

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