SOLUTION: a body starts with intial velocity 30m/s and a retardation of4m/s square. find the distance travelled by the body in the 8th second
Algebra.Com
Question 1063035: a body starts with intial velocity 30m/s and a retardation of4m/s square. find the distance travelled by the body in the 8th second
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
d(t) = ((-4*t^2)/2) + 30t
:
d(8) = (-4(8^2)/2) + 30*8 = 112 meters
:
The general form is
:
s = v(i)*t + (1/2)*a*t^2, where s is distance, v(i) is initial velocity, a is acceleration and t is time
:
RELATED QUESTIONS
S=ut + at 2 means ( at ) square
gives the distance S passed over by a moving body in t... (answered by math-vortex)
When a body is projected vertically upwards with the velocity v=7m/s, the height s... (answered by rothauserc)
The position of a 140kg body is given by S = 3t^2 - 7t + 4. Where S is in meters and t is (answered by Fombitz)
A body starts from rest and moves with a uniform acceleration of 4m/s2 until it travels a (answered by Alan3354)
distance travelled by a freely falling in the last second of it's motion, to that in the... (answered by Alan3354)
The net force on a 2-kg body is 6 N. If the body is originally travelling with a velocity (answered by ikleyn)
What is the distance travelled by a freeling falling body of height 45m in last one... (answered by solver91311)
when a body is being uniformly accelerated, the distance, D travelled is the sum of two... (answered by htmentor)
Calculate the distance travelled by a car with a velocity of 30/s it increase its speed... (answered by Alan3354)