SOLUTION: Hi! I am the father of an exasperated 9th grader. Thank you SO MUCH for being there! Here is the question that is stumping her: A boat travels 35km upstream and then back again

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Question 1060014: Hi! I am the father of an exasperated 9th grader. Thank you SO MUCH for being there! Here is the question that is stumping her:
A boat travels 35km upstream and then back again in 4 hours 48 minutes. If the speed of the boat in still water is 15km/hr, what is the speed of the current?
Thank you,
Tim in Massachusetts

Answer by ikleyn(52814)   (Show Source): You can put this solution on YOUR website!
.
Hi! I am the father of an exasperated 9th grader. Thank you SO MUCH for being there! Here is the question that is stumping her:
A boat travels 35 km upstream and then back again in 4 hours 48 minutes. If the speed of the boat in still water is 15 km/hr, what is the speed of the current?
Thank you,
Tim in Massachusetts
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Let "v" be the speed of the current, in km/h.

Then the speed of the boat traveling upstream   is (15-v) km/h,
     the speed of the boat traveling downstream is (15+v) km/h.

The time traveling 35 km upstream   is  hours.
The time traveling 35 km downstream is  hours.

The total time is 4 hours 48 minutes =   hour =   hour =  hour, 
which gives an equation 

 = .

To solve it, multiply both sides by 5*(15-v)*(15+v). You will get

35*5*(15+v) + 35*5*(15-v) = 24*(225-v^2),

24v^2 = 24*225 - 2*35*5*15 = 150,

v^2 =  = ,

v =  =  = 2.5 km/h.

Answer.  The speed of the current is 2.5 km/h.

Solved.


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