SOLUTION: Jane walked 4 miles her average speed was 3.2 miles per her. She spent 15 minutes longer on the last two miles than on the first two miles. how much did she spend on the first two

Question 1058472: Jane walked 4 miles her average speed was 3.2 miles per her. She spent 15 minutes longer on the last two miles than on the first two miles. how much did she spend on the first two miles.
Found 3 solutions by josgarithmetic, josmiceli, ikleyn:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
Fifteen minutes is same as .

RATE TIME DISTANCE FIRST 2/t t 2 LAST 2/(t+1/4) t+1/4 2 AVERAGE 3.2 Total t+(t+1/4) 4

AVERAGE rate given as 3.2, and the rate for the average is the distance divided by the time; the TOTALS.

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
hrs
Let = time spent on 1st 2 miles
= time in hrs spent on last 2 miles
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and

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She spent 1/2 hr on the 1st 2 miles

Answer by ikleyn(52800)   (Show Source): You can put this solution on YOUR website!
.
Jane walked 4 miles her average speed was 3.2 miles per her. She spent 15 minutes longer on the last two miles
than on the first two miles. how much did she spend on the first two miles.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

1. The total time spent for the walk is = 1.25 hours = hours. 2. From hours distract 15 min = of an hour, and divide the result by 2. You will get of an hour. It is the time Jane spent in the first two miles.

Answer. of an hour.

Simple as a cucumber.

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