SOLUTION: A rowing team rowed 90 miles while going with the current in the same amount of time as it took to row 10 miles going against the current. The rate of the current was 4 mph. Find
Algebra.Com
Question 1057033: A rowing team rowed 90 miles while going with the current in the same amount of time as it took to row 10 miles going against the current. The rate of the current was 4 mph. Find the rate of the rowing team in Stillwater.
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Let s be the rate of the team in still water. Then:
90/s+4=10/s-4
90s-360=10s+40
80s=400
s=5
The rate of the team in still water is 5 mph. ☺☺☺☺
RELATED QUESTIONS
A rowing team rowed 90 miles while going with the current in the same amount of time as... (answered by lwsshak3)
a rowing team rowed 90 miles while going with the current in the same amount of time as... (answered by stanbon)
A rowing team rowed
60
miles while going with the current in the same amount of time... (answered by ikleyn)
A rowing team rowed 60 miles while going with current in the same amount of time as it... (answered by mananth)
A rowing team rowed 50 miles while going with the current in the same amount of time as... (answered by mananth)
A rowing team rowed
60 miles while going with the current in the same amount of time as (answered by lwsshak3)
A rowing team rowed 60 miles while going with the current in the same amount of time as... (answered by josgarithmetic,Boreal)
A rowing team rowed
100
miles while going with the current in the same amount of time (answered by jorel555)
A rowing team rode 16 miles while going with the current in the same amount of time as it (answered by jorel555)