SOLUTION: Latoya's boat has a top speed of 20 mph in still water. While traveling on a river at top speed, she went 40 miles upstream in the same amount of time she went 60 miles downstream.

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Question 1057002: Latoya's boat has a top speed of 20 mph in still water. While traveling on a river at top speed, she went 40 miles upstream in the same amount of time she went 60 miles downstream. Find the rate of the river current.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
               SPEED         TIME        DISTANCE
UPSTRM         r-c           t           u
DOWNSTRM       r+c           t           d


The rule for constant travel rate is RT=D.

You know what to do. Right?

Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
.
Latoya's boat has a top speed of 20 mph in still water. While traveling on a river at top speed, she went 40 miles upstream
in the same amount of time she went 60 miles downstream. Find the rate of the river current.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Let "v" be the rate of the river current.

Then the speed of the boat upstream is 20-v mph,
while its speed downstream is 20+v mph.

The condition says 

 = .

It is yours governing equation. 
To solve it, multiply both sides by (20-v)*(20+v). You will get

40*(20+v) = 60*(20-v),   or

800 + 40v = 1200 - 60v,

40v + 60v = 1200 - 800,

100v = 400,

v = 4.

Answer. The rate of the river current is 4 mph.


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