SOLUTION: A man leaves his home driving his car on a business trip. Twenty minutes later, his wife discovers that he left his briefcase behind and decides to overtake him in another car. I

Question 1054357: A man leaves his home driving his car on a business trip. Twenty minutes later, his wife discovers that he left his briefcase behind and decides to overtake him in another car. If the wife knows that her husband drives at an average of 45 kph and she averages 60 kph, how long (in hours) will it take her to overtake her husband?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A man leaves his home driving his car on a business trip. Twenty minutes later, his wife discovers that he left his briefcase behind and decides to overtake him in another car. If the wife knows that her husband drives at an average of 45 kph and she averages 60 kph, how long (in hours) will it take her to overtake her husband?
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Husband DATA:
rate = 45 km/h ; time = x hrs ; dist = 45x km
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Wife DATA:
rate = 60 km/h ; time = x - (1/3) hr ; dist = 60x - 20 km
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Equation:
dist = dist
45x = 60x - 20
15x = 20
Ans:: x = 4/3 hr = 1 hr 20 min
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Cheers,
Stan H.
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