SOLUTION: an athlete throws a javelin from height of 1.5 meters the horizontal velocity is 9.8 meters per second. (Assume the accerlation due to gravity is 9.8 meters per second).
a) Writ
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Question 105335: an athlete throws a javelin from height of 1.5 meters the horizontal velocity is 9.8 meters per second. (Assume the accerlation due to gravity is 9.8 meters per second).
a) Write a parametic equation that describes the position of the javelin at time t.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
no vertical velocity?
x=9.8t
y=-4.9t^2+1.5
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