SOLUTION:
Suppose that a cyclist began a 476
mi ride across a state at the western edge of the​ state, at the same time that a car traveling toward it leaves the eastern end of
Algebra.Com
Question 1050961:
Suppose that a cyclist began a 476
mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after 8.5
hr and the car traveled 39.6
mph faster than the bicycle, find the average rate of each.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Hint: The car travelled 39.6 times 8.5 miles farther than the bicycle and the sum of the distances travelled is 476. Average speed is distance travelled divided by the time.
So
\ =\ 476)
Solve for 
. Then divide by 8.5 to find the average speed of the bicycle. The average speed of the car is 39.6 mph faster than that.
John
My calculator said it, I believe it, that settles it
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