SOLUTION: if you want to travel an average of 50/mi per hour on a trip and half of the trip you go 25/mi per hour how fast do you have to travel in the second half
Question 1050765: if you want to travel an average of 50/mi per hour on a trip and half of the trip you go 25/mi per hour how fast do you have to travel in the second half Found 4 solutions by josgarithmetic, Alan3354, stanbon, ikleyn:Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website! How do you measure the trip? Distance?
Try that.
Constant Travel Rate Rule is as D/T=R, D for distance and T for time.
RATE TIME DISTANCE
First 25 d
Second r d
Total 2d
AVERAGE 50
Average rate is given and time sum will give .
Two variables in one equation but simplification will change that. Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website! if you want to travel an average of 50/mi per hour on a trip and half of the trip you go 25/mi per hour how fast do you have to travel in the second half
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This is a "trick question."
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Pick a distance, say 100 miles.
If you go 25 mi/hr for 1/2 of it, 50 miles, it takes 2 hours.
To make 100 miles at an average speed of 50 mi/hr takes 2 hours.
Time is up.
It's not possible.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website! if you want to travel an average of 50/mi per hour on a trip and half of the trip you go 25/mi per hour how fast do you have to travel in the second half
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2nd half DATA:
rate = 25 mph ; distance = x miles ; time = x/25 hrs
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Final Results::
rate = 50 mph ; distance = 2x miles ; time = (2x)/50 hrs = x/25 hrs
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2nd half DATA:
distance = x miles ; time = (x/25)-(x/25) = 0 ; rate = x/0 = infinity
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After the 1st half at 25 mph there is zero time for the
2nd half trip if the average rate is to be 50 mph.
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Cheers,
Stan H.