SOLUTION: A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, t
Question 1050351: A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, the wind is still blowing at the same speed, so the return trip takes only 1 hour 12 minutes. What is his speed in still air, and how fast is the wind blowing?
Solve: We'll use substitution. After moving -1*v to the right, we get: , or . Substitute that
into another equation: and simplify: So, we know that v=30. Since , u=120.
Answer: .
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website! A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, the wind is still blowing at the same speed, so the return trip takes only 1 hour 12 minutes. What is his speed in still air, and how fast is the wind blowing?
--------------
Find the 2 groundspeeds upwind and downwind using d = r*t
---
The plane's airspeed is the average of the 2.
Windspeed = difference between airspeed and groundspeed.