SOLUTION: two friends live 1.1 miles apart along the same road. If they walk toward each other at rates that differ by 1/2 mph and they meet 12 minutes later, how fast is each person walking
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Question 1049517: two friends live 1.1 miles apart along the same road. If they walk toward each other at rates that differ by 1/2 mph and they meet 12 minutes later, how fast is each person walking?
Found 3 solutions by jorel555, ewatrrr, advanced_Learner:
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Let n be the slower walker. Then:
1/5(n)+1/5(n+1/2)=11/10
2n+2(n+1/2)=11
4n+1=11
4n=10
n=2.5 mph
n+1/2=3 mph. ☺☺☺☺
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
D = rt
D/t = r
1.1/.2 = average speed
5.5mph = combined speed
(r + (r+.5))= 5.5
2r = 5
r = 2.5mph
r + .5 = 3mph
2.5mph and 3mph the two rates
Answer by advanced_Learner(501) (Show Source): You can put this solution on YOUR website!
first friend
speed
time
distance
second friend
speed
time
distance *
given also
distance
the equations are
+*=
+=
multiply by on each side
+=
=
=
=
=
=
the rate of the first friend is = and the rate of the second firend is =
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