SOLUTION: Dan left school and drove east on Mass Pike at 55 mph. One hour later, Joe left school and traveled west on the Mass Pike at 50 miles per hour. How long will Dan have traveled when

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Question 1049380: Dan left school and drove east on Mass Pike at 55 mph. One hour later, Joe left school and traveled west on the Mass Pike at 50 miles per hour. How long will Dan have traveled when he and Joe are 300 miles apart?
Found 2 solutions by addingup, advanced_Learner:
Answer by addingup(3677)   (Show Source): You can put this solution on YOUR website!
55(x+1)+50x = 300
55x+55+50x = 300
105x = 245
x = 245/105 = 2.33 hours or 0.3333*60 = 20 thus 2 hours and 20 minutes
Note: There are 60 minutes in an hour, this is why 0.3333 of an hour times 60
Answer by advanced_Learner(501)   (Show Source): You can put this solution on YOUR website!
dan
time
distance
speed

joe
time
speed
distance
=+
Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: t=2.33333333333333.
  • Graphical form: Equation was fully solved.
  • Text form: 105t=245 simplifies to 0=0
  • Cartoon (animation) form:
    For tutors: simplify_cartoon( 105t=245 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at .
Moved these terms to the left highlight_green%28+-245+%29
It becomes .
Look at .
Solved linear equation highlight_red%28+105%2At-245=0+%29 equivalent to 105*t-245 =0
It becomes .
Result:
This is an equation! Solutions: t=2.33333333333333.

Universal Simplifier and Solver


Done!
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